A note on jQuery .unique()
I was dealing with an array full of years (2009, 2009, 2010, 2010, 2009, 2010), and I wanted to easily remove duplicate entries in the array.
I found that jQuery had a .unique() function that removes duplicates. However, there if the duplicates are not in a sequential order, it will miss some of the items in the array.
$.unique(yearArray);
This returns 2009, 2010, 2009, 2010. The function missed a couple of the duplicates. This is simply fixed by sorting the array and then passing it into the unique function.
yearArray.sort();
$.unique(yearArray);
This should then return 2010, 2009. Hope this helps. 
!! UPDATE !!
I hate Internet Explorer. I just discovered that the .unique() function works with DOM objects and because IE sucks, it doesn’t work properly. So, I had to replace the .unique() with the following code:
// still sort the array
yearArray.sort();
//$.unique(yearArray);
yearArray = uniqueArray(yearArray);
function uniqueArray(a){
temp = new Array();
for(var i = 0; i < a.length; i ++){
if(!contains(temp, a[i])){
temp.length+=1;
temp[temp.length-1] = a[i];
}
}
return temp;
}
function contains(a, e){
for(j=0;j<a.length;j++)if(a[j]==e)return true;
return false;
}
More code, but it works in all browsers now.
Thanks to Developer Snippets for the code
